1/5(5x-2)=x-7

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Solution for 1/5(5x-2)=x-7 equation: 



1/5(5x-2)=x-7

We move all terms to the left:

1/5(5x-2)-(x-7)=0



Domain of the equation: 5(5x-2)!=0

x∈R



We get rid of parentheses

1/5(5x-2)-x+7=0

We multiply all the terms by the denominator


-x*5(5x-2)+7*5(5x-2)+1=0

Wy multiply elements

-5x^2(5+35x(5+1=0

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