1/5(5y+10)-8=-1/8(24y-48)

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Solution for 1/5(5y+10)-8=-1/8(24y-48) equation: 



1/5(5y+10)-8=-1/8(24y-48)

We move all terms to the left:

1/5(5y+10)-8-(-1/8(24y-48))=0



Domain of the equation: 5(5y+10)!=0

y∈R





Domain of the equation: 8(24y-48))!=0

y∈R



We calculate fractions


(8y2/(5(5y+10)*8(24y-48)))+(-(-5y5)/(5(5y+10)*8(24y-48)))-8=0



We calculate terms in parentheses: +(8y2/(5(5y+10)*8(24y-48))), so:

8y2/(5(5y+10)*8(24y-48))

We multiply all the terms by the denominator


8y2

We add all the numbers together, and all the variables

8y^2

Back to the equation:

+(8y^2)





We calculate terms in parentheses: +(-(-5y5)/(5(5y+10)*8(24y-48))), so:

-(-5y5)/(5(5y+10)*8(24y-48))

We add all the numbers together, and all the variables

-(-5y^5)/(5(5y+10)*8(24y-48))

We multiply all the terms by the denominator


-(-5y^5)

We do not support eypression: y^5

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