1/5(7j+9)=7/5j-2

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Solution for 1/5(7j+9)=7/5j-2 equation: 



1/5(7j+9)=7/5j-2

We move all terms to the left:

1/5(7j+9)-(7/5j-2)=0



Domain of the equation: 5(7j+9)!=0

j∈R





Domain of the equation: 5j-2)!=0

j∈R



We get rid of parentheses

1/5(7j+9)-7/5j+2=0

We calculate fractions


5j/(175j^2+225j)+(-35j7/(175j^2+225j)+2=0

We calculate fractions

We do not support ejpression: j^3

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