1/5(8+4x)-10x=2(x+6)

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Solution for 1/5(8+4x)-10x=2(x+6) equation: 



1/5(8+4x)-10x=2(x+6)

We move all terms to the left:

1/5(8+4x)-10x-(2(x+6))=0



Domain of the equation: 5(8+4x)!=0

x∈R



We add all the numbers together, and all the variables

1/5(4x+8)-10x-(2(x+6))=0

We add all the numbers together, and all the variables

-10x+1/5(4x+8)-(2(x+6))=0

We multiply all the terms by the denominator


-10x*5(4x+8)-((2(x+6)))*5(4x+8)+1=0



We calculate terms in parentheses: -((2(x+6)))*5(4x+8), so:

(2(x+6)))*5(4x+8



Wy multiply elements

-50x^2(4-((2(x+6)))*5(4x+8)+1=0

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