1/5(8x-24)=1/2(-6x-2)

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Solution for 1/5(8x-24)=1/2(-6x-2) equation:



1/5(8x-24)=1/2(-6x-2)
We move all terms to the left:
1/5(8x-24)-(1/2(-6x-2))=0
Domain of the equation: 5(8x-24)!=0
x∈R
Domain of the equation: 2(-6x-2))!=0
x∈R
We calculate fractions
(2x(-)/(5(8x-24)*2(-6x-2)))+(-5x8/(5(8x-24)*2(-6x-2)))=0
We calculate terms in parentheses: +(2x(-)/(5(8x-24)*2(-6x-2))), so:
2x(-)/(5(8x-24)*2(-6x-2))
We add all the numbers together, and all the variables
2x0/(5(8x-24)*2(-6x-2))
We multiply all the terms by the denominator
2x0
We add all the numbers together, and all the variables
2x
Back to the equation:
+(2x)
We calculate terms in parentheses: +(-5x8/(5(8x-24)*2(-6x-2))), so:
-5x8/(5(8x-24)*2(-6x-2))
We multiply all the terms by the denominator
-5x8
We add all the numbers together, and all the variables
-5x^8
We do not support expression: x^8

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