1/5(a+1)=1/3(2a-3)

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Solution for 1/5(a+1)=1/3(2a-3) equation:



1/5(a+1)=1/3(2a-3)
We move all terms to the left:
1/5(a+1)-(1/3(2a-3))=0
Domain of the equation: 5(a+1)!=0
a∈R
Domain of the equation: 3(2a-3))!=0
a∈R
We calculate fractions
(3a2/(5(a+1)*3(2a-3)))+(-5aa/(5(a+1)*3(2a-3)))=0
We calculate terms in parentheses: +(3a2/(5(a+1)*3(2a-3))), so:
3a2/(5(a+1)*3(2a-3))
We multiply all the terms by the denominator
3a2
We add all the numbers together, and all the variables
3a^2
Back to the equation:
+(3a^2)
We calculate terms in parentheses: +(-5aa/(5(a+1)*3(2a-3))), so:
-5aa/(5(a+1)*3(2a-3))
We multiply all the terms by the denominator
-5aa
Back to the equation:
+(-5aa)
We get rid of parentheses
3a^2-5aa=0

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