1/5(a+1)=1/3(2a-3)

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Solution for 1/5(a+1)=1/3(2a-3) equation: 



1/5(a+1)=1/3(2a-3)

We move all terms to the left:

1/5(a+1)-(1/3(2a-3))=0



Domain of the equation: 5(a+1)!=0

a∈R





Domain of the equation: 3(2a-3))!=0

a∈R



We calculate fractions


(3a2/(5(a+1)*3(2a-3)))+(-5aa/(5(a+1)*3(2a-3)))=0



We calculate terms in parentheses: +(3a2/(5(a+1)*3(2a-3))), so:

3a2/(5(a+1)*3(2a-3))

We multiply all the terms by the denominator


3a2

We add all the numbers together, and all the variables

3a^2

Back to the equation:

+(3a^2)





We calculate terms in parentheses: +(-5aa/(5(a+1)*3(2a-3))), so:

-5aa/(5(a+1)*3(2a-3))

We multiply all the terms by the denominator


-5aa

Back to the equation:

+(-5aa)



We get rid of parentheses

3a^2-5aa=0

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