1/5(a+5)=1/3(5-a)

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Solution for 1/5(a+5)=1/3(5-a) equation: 



1/5(a+5)=1/3(5-a)

We move all terms to the left:

1/5(a+5)-(1/3(5-a))=0



Domain of the equation: 5(a+5)!=0

a∈R





Domain of the equation: 3(5-a))!=0

a∈R



We add all the numbers together, and all the variables

1/5(a+5)-(1/3(-1a+5))=0

We calculate fractions


(3a(-)/(5(a+5)*3(-1a+5)))+(-5aa/(5(a+5)*3(-1a+5)))=0



We calculate terms in parentheses: +(3a(-)/(5(a+5)*3(-1a+5))), so:

3a(-)/(5(a+5)*3(-1a+5))

We add all the numbers together, and all the variables

3a0/(5(a+5)*3(-1a+5))

We multiply all the terms by the denominator


3a0

We add all the numbers together, and all the variables

3a

Back to the equation:

+(3a)





We calculate terms in parentheses: +(-5aa/(5(a+5)*3(-1a+5))), so:

-5aa/(5(a+5)*3(-1a+5))

We multiply all the terms by the denominator


-5aa

Back to the equation:

+(-5aa)



We get rid of parentheses

3a-5aa=0

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