1/5(a-4)=2/5(3-2a)

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Solution for 1/5(a-4)=2/5(3-2a) equation:



1/5(a-4)=2/5(3-2a)
We move all terms to the left:
1/5(a-4)-(2/5(3-2a))=0
Domain of the equation: 5(a-4)!=0
a∈R
Domain of the equation: 5(3-2a))!=0
a∈R
We add all the numbers together, and all the variables
1/5(a-4)-(2/5(-2a+3))=0
We calculate fractions
(5a(-)/(5(a-4)*5(-2a+3)))+(-10aa/(5(a-4)*5(-2a+3)))=0
We calculate terms in parentheses: +(5a(-)/(5(a-4)*5(-2a+3))), so:
5a(-)/(5(a-4)*5(-2a+3))
We add all the numbers together, and all the variables
5a0/(5(a-4)*5(-2a+3))
We multiply all the terms by the denominator
5a0
We add all the numbers together, and all the variables
5a
Back to the equation:
+(5a)
We calculate terms in parentheses: +(-10aa/(5(a-4)*5(-2a+3))), so:
-10aa/(5(a-4)*5(-2a+3))
We multiply all the terms by the denominator
-10aa
Back to the equation:
+(-10aa)
We get rid of parentheses
5a-10aa=0

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