1/5(b+10)=2

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Solution for 1/5(b+10)=2 equation: 



1/5(b+10)=2

We move all terms to the left:

1/5(b+10)-(2)=0



Domain of the equation: 5(b+10)!=0

b∈R



We multiply all the terms by the denominator


-2*5(b+10)+1=0

Wy multiply elements

-10b(b+1=0

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