1/5(b+3)=2

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Solution for 1/5(b+3)=2 equation: 


b in (-oo:+oo)

(1/5)*(b+3) = 2 // - 2

(1/5)*(b+3)-2 = 0

1/5*(b+3)-2 = 0

1/5*(b+3)-2 = 0

1/5*b-7/5 = 0

1/5*b-7/5 = 0

1/5*b-7/5 = 0 // + 7/5

1/5*b = 7/5 // : 1/5

b = 7/5/1/5

b = 7

b = 7

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