1/5(k+5)=2(k-1)

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Solution for 1/5(k+5)=2(k-1) equation:



1/5(k+5)=2(k-1)
We move all terms to the left:
1/5(k+5)-(2(k-1))=0
Domain of the equation: 5(k+5)!=0
k∈R
We multiply all the terms by the denominator
-((2(k-1)))*5(k+5)+1=0
We calculate terms in parentheses: -((2(k-1)))*5(k+5), so:
(2(k-1)))*5(k+5
We calculate terms in parentheses: -((2(k-1)))*5(k+5), so:
(2(k-1)))*5(k+5
We calculate terms in parentheses: -((2(k-1)))*5(k+5), so:
(2(k-1)))*5(k+5
We calculate terms in parentheses: -((2(k-1)))*5(k+5), so:
(2(k-1)))*5(k+5
We calculate terms in parentheses: -((2(k-1)))*5(k+5), so:
(2(k-1)))*5(k+5
We calculate terms in parentheses: -((2(k-1)))*5(k+5), so:
(2(k-1)))*5(k+5
We calculate terms in parentheses: -((2(k-1)))*5(k+5), so:
(2(k-1)))*5(k+5
We calculate terms in parentheses: -((2(k-1)))*5(k+5), so:
(2(k-1)))*5(k+5
We calculate terms in parentheses: -((2(k-1)))*5(k+5), so:
(2(k-1)))*5(k+5
We calculate terms in parentheses: -((2(k-1)))*5(k+5), so:
(2(k-1)))*5(k+5
We calculate terms in parentheses: -((2(k-1)))*5(k+5), so:
(2(k-1)))*5(k+5
We calculate terms in parentheses: -((2(k-1)))*5(k+5), so:
(2(k-1)))*5(k+5
We calculate terms in parentheses: -((2(k-1)))*5(k+5), so:
(2(k-1)))*5(k+5
We calculate terms in parentheses: -((2(k-1)))*5(k+5), so:
(2(k-1)))*5(k+5
We calculate terms in parentheses: -((2(k-1)))*5(k+5), so:
(2(k-1)))*5(k+5
We calculate terms in parentheses: -((2(k-1)))*5(k+5), so:
(2(k-1)))*5(k+5
We calculate terms in parentheses: -((2(k-1)))*5(k+5), so:
(2(k-1)))*5(k+5
We calculate terms in parentheses: -((2(k-1)))*5(k+5), so:
(2(k-1)))*5(k+5
We calculate terms in parentheses: -((2(k-1)))*5(k+5), so:
(2(k-1)))*5(k+5
We calculate terms in parentheses: -((2(k-1)))*5(k+5), so:
(2(k-1)))*5(k+5
We calculate terms in parentheses: -((2(k-1)))*5(k+5), so:
(2(k-1)))*5(k+5
We calculate terms in parentheses: -((2(k-1)))*5(k+5), so:
(2(k-1)))*5(k+5
We calculate terms in parentheses: -((2(k-1)))*5(k+5), so:
(2(k-1)))*5(k+5
We calculate terms in parentheses: -((2(k-1)))*5(k+5), so:
(2(k-1)))*5(k+5
We calculate terms in parentheses: -((2(k-1)))*5(k+5), so:
(2(k-1)))*5(k+5
We calculate terms in parentheses: -((2(k-1)))*5(k+5), so:
(2(k-1)))*5(k+5
We calculate terms in parentheses: -((2(k-1)))*5(k+5), so:
(2(k-1)))*5(k+5
We calculate terms in parentheses: -((2(k-1)))*5(k+5), so:
(2(k-1)))*5(k+5
We calculate terms in parentheses: -((2(k-1)))*5(k+5), so:
(2(k-1)))*5(k+5
We calculate terms in parentheses: -((2(k-1)))*5(k+5), so:
(2(k-1)))*5(k+5
We calculate terms in parentheses: -((2(k-1)))*5(k+5), so:
(2(k-1)))*5(k+5
We calculate terms in parentheses: -((2(k-1)))*5(k+5), so:
(2(k-1)))*5(k+5
We calculate terms in parentheses: -((2(k-1)))*5(k+5), so:
(2(k-1)))*5(k+5
We calculate terms in parentheses: -((2(k-1)))*5(k+5), so:
(2(k-1)))*5(k+5
We calculate terms in parentheses: -((2(k-1)))*5(k+5), so:
(2(k-1)))*5(k+5
We calculate terms in parentheses: -((2(k-1)))*5(k+5), so:
(2(k-1)))*5(k+5
We calculate terms in parentheses: -((2(k-1)))*5(k+5), so:
(2(k-1)))*5(k+5
We calculate terms in parentheses: -((2(k-1)))*5(k+5), so:
(2(k-1)))*5(k+5
We calculate terms in parentheses: -((2(k-1)))*5(k+5), so:
(2(k-1)))*5(k+5
We calculate terms in parentheses: -((2(k-1)))*5(k+5), so:
(2(k-1)))*5(k+5
We calculate terms in parentheses: -((2(k-1)))*5(k+5), so:
(2(k-1)))*5(k+5
We calculate terms in parentheses: -((2(k-1)))*5(k+5), so:
(2(k-1)))*5(k+5
We calculate terms in parentheses: -((2(k-1)))*5(k+5), so:
(2(k-1)))*5(k+5
We calculate terms in parentheses: -((2(k-1)))*5(k+5), so:
(2(k-1)))*5(k+5

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