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1/5(k-3)=3/5
We move all terms to the left:
1/5(k-3)-(3/5)=0
Domain of the equation: 5(k-3)!=0We add all the numbers together, and all the variables
k∈R
1/5(k-3)-(+3/5)=0
We get rid of parentheses
1/5(k-3)-3/5=0
We calculate fractions
=0
k=0/1
k=0
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