If it's not what You are looking for type in the equation solver your own equation and let us solve it.
1/5(m+2)=3/5-m
We move all terms to the left:
1/5(m+2)-(3/5-m)=0
Domain of the equation: 5(m+2)!=0
m∈R
Domain of the equation: 5-m)!=0We add all the numbers together, and all the variables
We move all terms containing m to the left, all other terms to the right
-m)!=-5
m!=-5/1
m!=-5
m∈R
1/5(m+2)-(-1m+3/5)=0
We get rid of parentheses
1/5(m+2)+1m-3/5=0
We calculate fractions
m=0
| 1/3+x/5=16/3x^2 | | 58/x=2 | | 241=187-y | | 2x+4x=1 | | -10-(-11)=x | | 2x+4x=11x+3x=5 | | y=0.1(1.23)^8 | | 249=29-x | | 3x(x-2)=8x^2-7x | | -4.8(x-3.75)=144.4 | | x+1.62=7.57 | | u-1.79=6.6 | | 1/3+k/5=16/3k^2 | | 13x-3=49 | | y-2.1=7.61 | | y^2+2/3y=0 | | 13=8+5u | | 25=8/3v | | 4•y=96 | | -33=x/5-3 | | 1624=28(p+10) | | 5t+7=T+15 | | 4u+4=32 | | -4x+6X-5=9 | | (8x-1)+27=90 | | 3(y+6)=33 | | 4d-8=8 | | X+3/3+x+6/2=2 | | (21/3)x+4=18 | | 8d+6=54 | | w/3.75=4 | | A=9/5(h-47) |