1/5(n+3)=1/4(n+2)

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Solution for 1/5(n+3)=1/4(n+2) equation: 



1/5(n+3)=1/4(n+2)

We move all terms to the left:

1/5(n+3)-(1/4(n+2))=0



Domain of the equation: 5(n+3)!=0

n∈R





Domain of the equation: 4(n+2))!=0

n∈R



We calculate fractions


(4nn/(5(n+3)*4(n+2)))+(-5nn/(5(n+3)*4(n+2)))=0



We calculate terms in parentheses: +(4nn/(5(n+3)*4(n+2))), so:

4nn/(5(n+3)*4(n+2))

We multiply all the terms by the denominator


4nn

Back to the equation:

+(4nn)





We calculate terms in parentheses: +(-5nn/(5(n+3)*4(n+2))), so:

-5nn/(5(n+3)*4(n+2))

We multiply all the terms by the denominator


-5nn

Back to the equation:

+(-5nn)



We get rid of parentheses

4nn-5nn=0

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