1/5(n+4)-7=16

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Solution for 1/5(n+4)-7=16 equation: 



1/5(n+4)-7=16

We move all terms to the left:

1/5(n+4)-7-(16)=0



Domain of the equation: 5(n+4)!=0

n∈R



We add all the numbers together, and all the variables

1/5(n+4)-23=0

We multiply all the terms by the denominator


-23*5(n+4)+1=0

Wy multiply elements

-115n(n+1=0

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