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1/5(p-14)=10+p
We move all terms to the left:
1/5(p-14)-(10+p)=0
Domain of the equation: 5(p-14)!=0We add all the numbers together, and all the variables
p∈R
1/5(p-14)-(p+10)=0
We get rid of parentheses
1/5(p-14)-p-10=0
We multiply all the terms by the denominator
-p*5(p-14)-10*5(p-14)+1=0
Wy multiply elements
-5p^2(p-50p(p+1=0
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