1/5(r-+6)=1/7(r+8)

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Solution for 1/5(r-+6)=1/7(r+8) equation: 



1/5(r-+6)=1/7(r+8)

We move all terms to the left:

1/5(r-+6)-(1/7(r+8))=0



Domain of the equation: 5(r-+6)!=0

r∈R





Domain of the equation: 7(r+8))!=0

r∈R



We add all the numbers together, and all the variables

1/5(+r)-(1/7(r+8))=0

We calculate fractions


(7rr/(5(+r)*7(r+8)))+(-5r0/(5(+r)*7(r+8)))=0



We calculate terms in parentheses: +(7rr/(5(+r)*7(r+8))), so:

7rr/(5(+r)*7(r+8))

We multiply all the terms by the denominator


7rr

Back to the equation:

+(7rr)





We calculate terms in parentheses: +(-5r0/(5(+r)*7(r+8))), so:

-5r0/(5(+r)*7(r+8))

We multiply all the terms by the denominator


-5r0

We add all the numbers together, and all the variables

-5r

Back to the equation:

+(-5r)



We get rid of parentheses

7rr-5r=0

We add all the numbers together, and all the variables

-5r+7rr=0

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