1/5(w-3)=1/6(w+4)

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Solution for 1/5(w-3)=1/6(w+4) equation: 



1/5(w-3)=1/6(w+4)

We move all terms to the left:

1/5(w-3)-(1/6(w+4))=0



Domain of the equation: 5(w-3)!=0

w∈R





Domain of the equation: 6(w+4))!=0

w∈R



We calculate fractions


(6ww/(5(w-3)*6(w+4)))+(-5ww/(5(w-3)*6(w+4)))=0



We calculate terms in parentheses: +(6ww/(5(w-3)*6(w+4))), so:

6ww/(5(w-3)*6(w+4))

We multiply all the terms by the denominator


6ww

Back to the equation:

+(6ww)





We calculate terms in parentheses: +(-5ww/(5(w-3)*6(w+4))), so:

-5ww/(5(w-3)*6(w+4))

We multiply all the terms by the denominator


-5ww

Back to the equation:

+(-5ww)



We get rid of parentheses

6ww-5ww=0

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