1/5(x+0.5)+5.25=3.2x+7/10(x+2.2)

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Solution for 1/5(x+0.5)+5.25=3.2x+7/10(x+2.2) equation: 



1/5(x+0.5)+5.25=3.2x+7/10(x+2.2)

We move all terms to the left:

1/5(x+0.5)+5.25-(3.2x+7/10(x+2.2))=0



Domain of the equation: 5(x+0.5)!=0

x∈R





Domain of the equation: 10(x+2.2))!=0

x∈R



We calculate fractions


(10xx/(5(x+0.5)*10(x+2.2)))+(-(3.2x+35xx)/(5(x+0.5)*10(x+2.2)))+5.25=0



We calculate terms in parentheses: +(10xx/(5(x+0.5)*10(x+2.2))), so:

10xx/(5(x+0.5)*10(x+2.2))

We multiply all the terms by the denominator


10xx

Back to the equation:

+(10xx)





We calculate terms in parentheses: +(-(3.2x+35xx)/(5(x+0.5)*10(x+2.2))), so:

-(3.2x+35xx)/(5(x+0.5)*10(x+2.2))

We add all the numbers together, and all the variables

-(+3.2x+35xx)/(5(x+0.5)*10(x+2.2))

We multiply all the terms by the denominator


-(+3.2x+35xx)

We get rid of parentheses

-3.2x-35xx

Back to the equation:

+(-3.2x-35xx)



We get rid of parentheses

10xx-3.2x-35xx+5.25=0

We add all the numbers together, and all the variables

-3.2x+10xx-35xx+5.25=0

We move all terms containing x to the left, all other terms to the right

-3.2x+10xx-35xx=-5.25

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