1/5(x+10)-7=1/3(x-9)

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Solution for 1/5(x+10)-7=1/3(x-9) equation: 



1/5(x+10)-7=1/3(x-9)

We move all terms to the left:

1/5(x+10)-7-(1/3(x-9))=0



Domain of the equation: 5(x+10)!=0

x∈R





Domain of the equation: 3(x-9))!=0

x∈R



We calculate fractions


(3xx/(5(x+10)*3(x-9)))+(-5xx/(5(x+10)*3(x-9)))-7=0



We calculate terms in parentheses: +(3xx/(5(x+10)*3(x-9))), so:

3xx/(5(x+10)*3(x-9))

We multiply all the terms by the denominator


3xx

Back to the equation:

+(3xx)





We calculate terms in parentheses: +(-5xx/(5(x+10)*3(x-9))), so:

-5xx/(5(x+10)*3(x-9))

We multiply all the terms by the denominator


-5xx

Back to the equation:

+(-5xx)



We get rid of parentheses

3xx-5xx-7=0

We move all terms containing x to the left, all other terms to the right

3xx-5xx=7

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