1/5(x+2)=1/10(x-6)

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Solution for 1/5(x+2)=1/10(x-6) equation: 



1/5(x+2)=1/10(x-6)

We move all terms to the left:

1/5(x+2)-(1/10(x-6))=0



Domain of the equation: 5(x+2)!=0

x∈R





Domain of the equation: 10(x-6))!=0

x∈R



We calculate fractions


(10xx/(5(x+2)*10(x-6)))+(-5xx/(5(x+2)*10(x-6)))=0



We calculate terms in parentheses: +(10xx/(5(x+2)*10(x-6))), so:

10xx/(5(x+2)*10(x-6))

We multiply all the terms by the denominator


10xx

Back to the equation:

+(10xx)





We calculate terms in parentheses: +(-5xx/(5(x+2)*10(x-6))), so:

-5xx/(5(x+2)*10(x-6))

We multiply all the terms by the denominator


-5xx

Back to the equation:

+(-5xx)



We get rid of parentheses

10xx-5xx=0

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