If it's not what You are looking for type in the equation solver your own equation and let us solve it.
1/5(x+2)=10
We move all terms to the left:
1/5(x+2)-(10)=0
Domain of the equation: 5(x+2)!=0We multiply all the terms by the denominator
x∈R
-10*5(x+2)+1=0
Wy multiply elements
-50x(x+1=0
| 3x+4x+5x=31 | | 3(x+2)+15=7x-5 | | F(u)=-3+6 | | w^2-14w+14=0 | | 3x+3x+126=180 | | 16=-5+4(-x+7) | | 0.4r=120 | | 8x+3=x-9 | | 16=-5+4(-x+7 | | 2x+1=7x=14 | | (14+x)+(2x+19)=12 | | (14+x)+(x+15)=13 | | 7y+4y-2y+11=26 | | 3x+x=344 | | 2x-58+3x-11=4x | | 14+x=x+15 | | 3x-1=4(1/3x+6) | | -3x-4(x+2)=11 | | 2. 5y-2+y-6=-9y+10+6y+13 | | x-1/4+x/3=1/6 | | 2^(3x+2)=48 | | 3(y-8)=2y+6 | | 2^3x+2=48 | | 10-52/t=26 | | -2(3x-8)-5=1 | | 3-(2x+5)=2 | | 11=h÷6+8 | | 4/11x+1/2=2/5-7/11x+2/5 | | 9=-2(x-3) | | 9=-2(x+2)=11 | | 4z/8=−24 | | (28b-8)-9(3b+3)=-5 |