1/5(x+20)=x+14+4/5x

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Solution for 1/5(x+20)=x+14+4/5x equation: 



1/5(x+20)=x+14+4/5x

We move all terms to the left:

1/5(x+20)-(x+14+4/5x)=0



Domain of the equation: 5(x+20)!=0

x∈R





Domain of the equation: 5x)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

1/5(x+20)-(x+4/5x+14)=0

We get rid of parentheses

1/5(x+20)-x-4/5x-14=0

We calculate fractions


-x+5x/(25x^2+500x)+(-20xx/(25x^2+500x)-14=0

We add all the numbers together, and all the variables

-1x+5x/(25x^2+500x)+(-20xx/(25x^2+500x)-14=0

We calculate fractions

We do not support expression: x^3

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