1/5(x+3y)=4/7(2x-1)

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Solution for 1/5(x+3y)=4/7(2x-1) equation: 


x in (-oo:+oo)

(1/5)*(x+3*y) = (4/7)*(2*x-1) // - (4/7)*(2*x-1)

(1/5)*(x+3*y)-((4/7)*(2*x-1)) = 0

(1/5)*(x+3*y)+(-4/7)*(2*x-1) = 0

1/5*(x+3*y)-4/7*(2*x-1) = 0

1/5*(x+3*y)-4/7*(2*x-1) = 0

3/5*y-33/35*x+4/7 = 0

3/5*y-33/35*x+4/7 = 0

3/5*y-33/35*x+4/7 = 0 // - 3/5*y+4/7

-33/35*x = -(3/5*y+4/7) // : -33/35

x = (-(3/5*y+4/7))/(-33/35)

x = 35/33*(3/5*y+4/7)

x = 35/33*(3/5*y+4/7)

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