1/5(x+50)-6=2/5(3x+20)

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Solution for 1/5(x+50)-6=2/5(3x+20) equation: 



1/5(x+50)-6=2/5(3x+20)

We move all terms to the left:

1/5(x+50)-6-(2/5(3x+20))=0



Domain of the equation: 5(x+50)!=0

x∈R





Domain of the equation: 5(3x+20))!=0

x∈R



We calculate fractions


(5x3/(5(x+50)*5(3x+20)))+(-10xx/(5(x+50)*5(3x+20)))-6=0



We calculate terms in parentheses: +(5x3/(5(x+50)*5(3x+20))), so:

5x3/(5(x+50)*5(3x+20))

We multiply all the terms by the denominator


5x3

We add all the numbers together, and all the variables

5x^3

We do not support expression: x^3

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