1/5(x+7)=1/4(14-2x)

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Solution for 1/5(x+7)=1/4(14-2x) equation: 



1/5(x+7)=1/4(14-2x)

We move all terms to the left:

1/5(x+7)-(1/4(14-2x))=0



Domain of the equation: 5(x+7)!=0

x∈R





Domain of the equation: 4(14-2x))!=0

x∈R



We add all the numbers together, and all the variables

1/5(x+7)-(1/4(-2x+14))=0

We calculate fractions


(4x(-)/(5(x+7)*4(-2x+14)))+(-5xx/(5(x+7)*4(-2x+14)))=0



We calculate terms in parentheses: +(4x(-)/(5(x+7)*4(-2x+14))), so:

4x(-)/(5(x+7)*4(-2x+14))

We add all the numbers together, and all the variables

4x0/(5(x+7)*4(-2x+14))

We multiply all the terms by the denominator


4x0

We add all the numbers together, and all the variables

4x

Back to the equation:

+(4x)





We calculate terms in parentheses: +(-5xx/(5(x+7)*4(-2x+14))), so:

-5xx/(5(x+7)*4(-2x+14))

We multiply all the terms by the denominator


-5xx

Back to the equation:

+(-5xx)



We get rid of parentheses

4x-5xx=0

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