1/5(x-1)+1/2(x+3)=2

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Solution for 1/5(x-1)+1/2(x+3)=2 equation:



1/5(x-1)+1/2(x+3)=2
We move all terms to the left:
1/5(x-1)+1/2(x+3)-(2)=0
Domain of the equation: 5(x-1)!=0
x∈R
Domain of the equation: 2(x+3)!=0
x∈R
We calculate fractions
(2xx/(5(x-1)*2(x+3))+(5xx/(5(x-1)*2(x+3))-2=0
We can not solve this equation

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