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1/5(x-12)=1/4(x-12)
We move all terms to the left:
1/5(x-12)-(1/4(x-12))=0
Domain of the equation: 5(x-12)!=0
x∈R
Domain of the equation: 4(x-12))!=0We calculate fractions
x∈R
(4xx/(5(x-12)*4(x-12)))+(-5xx/(5(x-12)*4(x-12)))=0
We calculate terms in parentheses: +(4xx/(5(x-12)*4(x-12))), so:
4xx/(5(x-12)*4(x-12))
We multiply all the terms by the denominator
4xx
Back to the equation:
+(4xx)
We calculate terms in parentheses: +(-5xx/(5(x-12)*4(x-12))), so:We get rid of parentheses
-5xx/(5(x-12)*4(x-12))
We multiply all the terms by the denominator
-5xx
Back to the equation:
+(-5xx)
4xx-5xx=0
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