1/5(x-2)=1/10(x+)

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Solution for 1/5(x-2)=1/10(x+) equation: 



1/5(x-2)=1/10(x+)

We move all terms to the left:

1/5(x-2)-(1/10(x+))=0



Domain of the equation: 5(x-2)!=0

x∈R





Domain of the equation: 10(x+))!=0

x∈R



We add all the numbers together, and all the variables

1/5(x-2)-(1/10(+x))=0

We calculate fractions


(10x(+)/(5(x-2)*10(+x)))+(-5xx/(5(x-2)*10(+x)))=0



We calculate terms in parentheses: +(10x(+)/(5(x-2)*10(+x))), so:

10x(+)/(5(x-2)*10(+x))

We add all the numbers together, and all the variables

10x0/(5(x-2)*10(+x))

We multiply all the terms by the denominator


10x0

We add all the numbers together, and all the variables

10x

Back to the equation:

+(10x)





We calculate terms in parentheses: +(-5xx/(5(x-2)*10(+x))), so:

-5xx/(5(x-2)*10(+x))

We multiply all the terms by the denominator


-5xx

Back to the equation:

+(-5xx)



We get rid of parentheses

10x-5xx=0

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