1/5(x-2)=110(x+6)

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Solution for 1/5(x-2)=110(x+6) equation:



1/5(x-2)=110(x+6)
We move all terms to the left:
1/5(x-2)-(110(x+6))=0
Domain of the equation: 5(x-2)!=0
x∈R
We multiply all the terms by the denominator
-((110(x+6)))*5(x-2)+1=0
We calculate terms in parentheses: -((110(x+6)))*5(x-2), so:
(110(x+6)))*5(x-2
We calculate terms in parentheses: -((110(x+6)))*5(x-2), so:
(110(x+6)))*5(x-2
We calculate terms in parentheses: -((110(x+6)))*5(x-2), so:
(110(x+6)))*5(x-2
We calculate terms in parentheses: -((110(x+6)))*5(x-2), so:
(110(x+6)))*5(x-2
We calculate terms in parentheses: -((110(x+6)))*5(x-2), so:
(110(x+6)))*5(x-2
We calculate terms in parentheses: -((110(x+6)))*5(x-2), so:
(110(x+6)))*5(x-2
We calculate terms in parentheses: -((110(x+6)))*5(x-2), so:
(110(x+6)))*5(x-2
We calculate terms in parentheses: -((110(x+6)))*5(x-2), so:
(110(x+6)))*5(x-2
We calculate terms in parentheses: -((110(x+6)))*5(x-2), so:
(110(x+6)))*5(x-2
We calculate terms in parentheses: -((110(x+6)))*5(x-2), so:
(110(x+6)))*5(x-2
We calculate terms in parentheses: -((110(x+6)))*5(x-2), so:
(110(x+6)))*5(x-2
We calculate terms in parentheses: -((110(x+6)))*5(x-2), so:
(110(x+6)))*5(x-2
We calculate terms in parentheses: -((110(x+6)))*5(x-2), so:
(110(x+6)))*5(x-2
We calculate terms in parentheses: -((110(x+6)))*5(x-2), so:
(110(x+6)))*5(x-2
We calculate terms in parentheses: -((110(x+6)))*5(x-2), so:
(110(x+6)))*5(x-2
We calculate terms in parentheses: -((110(x+6)))*5(x-2), so:
(110(x+6)))*5(x-2
We calculate terms in parentheses: -((110(x+6)))*5(x-2), so:
(110(x+6)))*5(x-2
We calculate terms in parentheses: -((110(x+6)))*5(x-2), so:
(110(x+6)))*5(x-2
We calculate terms in parentheses: -((110(x+6)))*5(x-2), so:
(110(x+6)))*5(x-2
We calculate terms in parentheses: -((110(x+6)))*5(x-2), so:
(110(x+6)))*5(x-2
We calculate terms in parentheses: -((110(x+6)))*5(x-2), so:
(110(x+6)))*5(x-2
We calculate terms in parentheses: -((110(x+6)))*5(x-2), so:
(110(x+6)))*5(x-2
We calculate terms in parentheses: -((110(x+6)))*5(x-2), so:
(110(x+6)))*5(x-2
We calculate terms in parentheses: -((110(x+6)))*5(x-2), so:
(110(x+6)))*5(x-2
We calculate terms in parentheses: -((110(x+6)))*5(x-2), so:
(110(x+6)))*5(x-2
We calculate terms in parentheses: -((110(x+6)))*5(x-2), so:
(110(x+6)))*5(x-2
We calculate terms in parentheses: -((110(x+6)))*5(x-2), so:
(110(x+6)))*5(x-2
We calculate terms in parentheses: -((110(x+6)))*5(x-2), so:
(110(x+6)))*5(x-2
We calculate terms in parentheses: -((110(x+6)))*5(x-2), so:
(110(x+6)))*5(x-2
We calculate terms in parentheses: -((110(x+6)))*5(x-2), so:
(110(x+6)))*5(x-2
We calculate terms in parentheses: -((110(x+6)))*5(x-2), so:
(110(x+6)))*5(x-2
We calculate terms in parentheses: -((110(x+6)))*5(x-2), so:
(110(x+6)))*5(x-2
We calculate terms in parentheses: -((110(x+6)))*5(x-2), so:
(110(x+6)))*5(x-2
We calculate terms in parentheses: -((110(x+6)))*5(x-2), so:
(110(x+6)))*5(x-2
We calculate terms in parentheses: -((110(x+6)))*5(x-2), so:
(110(x+6)))*5(x-2
We calculate terms in parentheses: -((110(x+6)))*5(x-2), so:
(110(x+6)))*5(x-2
We calculate terms in parentheses: -((110(x+6)))*5(x-2), so:
(110(x+6)))*5(x-2
We calculate terms in parentheses: -((110(x+6)))*5(x-2), so:
(110(x+6)))*5(x-2
We calculate terms in parentheses: -((110(x+6)))*5(x-2), so:
(110(x+6)))*5(x-2
We calculate terms in parentheses: -((110(x+6)))*5(x-2), so:
(110(x+6)))*5(x-2
We calculate terms in parentheses: -((110(x+6)))*5(x-2), so:
(110(x+6)))*5(x-2
We calculate terms in parentheses: -((110(x+6)))*5(x-2), so:
(110(x+6)))*5(x-2
We calculate terms in parentheses: -((110(x+6)))*5(x-2), so:
(110(x+6)))*5(x-2

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