1/5(x-3)=1/2(x+6)

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Solution for 1/5(x-3)=1/2(x+6) equation: 



1/5(x-3)=1/2(x+6)

We move all terms to the left:

1/5(x-3)-(1/2(x+6))=0



Domain of the equation: 5(x-3)!=0

x∈R





Domain of the equation: 2(x+6))!=0

x∈R



We calculate fractions


(2xx/(5(x-3)*2(x+6)))+(-5xx/(5(x-3)*2(x+6)))=0



We calculate terms in parentheses: +(2xx/(5(x-3)*2(x+6))), so:

2xx/(5(x-3)*2(x+6))

We multiply all the terms by the denominator


2xx

Back to the equation:

+(2xx)





We calculate terms in parentheses: +(-5xx/(5(x-3)*2(x+6))), so:

-5xx/(5(x-3)*2(x+6))

We multiply all the terms by the denominator


-5xx

Back to the equation:

+(-5xx)



We get rid of parentheses

2xx-5xx=0

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