1/5(x-4)=4x-3(x-1)+13/5

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Solution for 1/5(x-4)=4x-3(x-1)+13/5 equation: 



1/5(x-4)=4x-3(x-1)+13/5

We move all terms to the left:

1/5(x-4)-(4x-3(x-1)+13/5)=0



Domain of the equation: 5(x-4)!=0

x∈R



We calculate fractions


()/5x+(-(x+65xx)/5x=0

We add all the numbers together, and all the variables

()/5x+(-(+x+65xx)/5x=0

We multiply all the terms by the denominator


(-(+x+65xx)+()=0



We calculate terms in parentheses: +(-(+x+65xx)+(), so:

-(+x+65xx)+(

We add all the numbers together, and all the variables

-(+x+65xx)

We get rid of parentheses

-x-65xx

We add all the numbers together, and all the variables

-1x-65xx

Back to the equation:

+(-1x-65xx)



We get rid of parentheses

-1x-65xx=0

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