1/5(x-4)=5x-4(x-1)+56/5

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Solution for 1/5(x-4)=5x-4(x-1)+56/5 equation: 



1/5(x-4)=5x-4(x-1)+56/5

We move all terms to the left:

1/5(x-4)-(5x-4(x-1)+56/5)=0



Domain of the equation: 5(x-4)!=0

x∈R



We calculate fractions


()/5x+(-(x+280xx)/5x=0

We add all the numbers together, and all the variables

()/5x+(-(+x+280xx)/5x=0

We multiply all the terms by the denominator


(-(+x+280xx)+()=0



We calculate terms in parentheses: +(-(+x+280xx)+(), so:

-(+x+280xx)+(

We add all the numbers together, and all the variables

-(+x+280xx)

We get rid of parentheses

-x-280xx

We add all the numbers together, and all the variables

-1x-280xx

Back to the equation:

+(-1x-280xx)



We get rid of parentheses

-1x-280xx=0

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