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x in (-oo:+oo)
(1/5)*(x-5) = (1/5)*x-1 // - (1/5)*x-1
(1/5)*(x-5)-((1/5)*x)+1 = 0
(1/5)*(x-5)+(-1/5)*x+1 = 0
1/5*(x-5)-x/5+1 = 0
(1/5*5*(x-5))/5-x/5+(1*5)/5 = 0
1/5*5*(x-5)-x+1*5 = 0
5-5 = 0
0 = 0
0/5 = 0
0/5 = 0 // * 5
0 = 0
x belongs to the empty set
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