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(2*x-71)/(4*x^2-(12*x)-160) = 0
((2*a)/3)*a = 0
x-(2/7) = 1-(x/2)
17;1;Y;6
2;3;1;5
| x^2-18x=4 | | -3y=-3x+5 | | 5t(t-7)= | | 8+0.5n=14 | | 11x+55=7x+31 | | (2x-71)/(4x^2-12x-160) | | 15x^4-27x^2=0 | | 4(x^2+5x)=6-3x | | 5x(-2x-4)= | | https://roads.advancedacademics.com/contentserver/content/roadssection/279369/questions/assessments/i-parallelperpendicularlinesquiz/geom_1_4_quiz_14q4.gif | | 6m+2m+7m+8n= | | X^6=10000 | | 2a/3a=0 | | x-2/7=1-x/2 | | 1/6w==102 | | f(x-1)= | | 4w-11w=49 | | 2m+33=6m-3 | | -2(y-5y)+8=-3(4y-y)+5+16y | | -2*-2*-1*-1*-1*-1*1*1*1*1= | | h=-4.9t^2+19.6t+0.5 | | 6x+12+8x-86=150 | | M^2-4m+1=-3 | | 3/5×22/× | | 4x+102+6x+28=108 | | Y=2.25x+2.44 | | 2x-8(2-x)=12 | | 3.3+x=19 | | 4x-35=-3x+35 | | 49.98*0.14x=35.98*0.18x | | 4(a-2)=2a(a+7) | | x+7+x+4+3x-2+x^2-2x=37 |