1/5(y+2)=6/5-y

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Solution for 1/5(y+2)=6/5-y equation:



1/5(y+2)=6/5-y
We move all terms to the left:
1/5(y+2)-(6/5-y)=0
Domain of the equation: 5(y+2)!=0
y∈R
Domain of the equation: 5-y)!=0
We move all terms containing y to the left, all other terms to the right
-y)!=-5
y!=-5/1
y!=-5
y∈R
We add all the numbers together, and all the variables
1/5(y+2)-(-1y+6/5)=0
We get rid of parentheses
1/5(y+2)+1y-6/5=0
We calculate fractions
y=0

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