1/5(y+3)+3=1/10(7y-4)-5

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Solution for 1/5(y+3)+3=1/10(7y-4)-5 equation:


1/5(y+3)+3=1/10(7y-4)-5

We simplify the equation to the form, which is simple to understand 
1/5(y+3)+3=1/10(7y-4)-5

Reorder the terms in parentheses
+( + 0.2y + 0.6)+3=0.1*(7y-4)-5

Remove unnecessary parentheses
 + 0.2y + 0.6+3=0.1+*(+7y-4+)-5

Reorder the terms in parentheses
 + 0.2y + 0.6+3=+( + 0.7y-0.4)-5

Remove unnecessary parentheses
 + 0.2y + 0.6+3=0.7y-0.4-5

We move all terms containing y to the left and all other terms to the right. 
 + 0.2y-0.7y=-0.4-5-0.6-3

We simplify left and right side of the equation. 
-0.5y=-9

We divide both sides of the equation by -0.5 to get y. 
y=18

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