1/5(y+3)+6=1/3(5y-2)-25

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Solution for 1/5(y+3)+6=1/3(5y-2)-25 equation: 



1/5(y+3)+6=1/3(5y-2)-25

We move all terms to the left:

1/5(y+3)+6-(1/3(5y-2)-25)=0



Domain of the equation: 5(y+3)!=0

y∈R





Domain of the equation: 3(5y-2)-25)!=0

y∈R



We calculate fractions


(3y5/(5(y+3)*3(5y-2))+(-5yy/(5(y+3)*3(5y-2))+6=0

We can not solve this equation

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