1/5(y+4)+5=1/3(5y-1)-32

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Solution for 1/5(y+4)+5=1/3(5y-1)-32 equation: 



1/5(y+4)+5=1/3(5y-1)-32

We move all terms to the left:

1/5(y+4)+5-(1/3(5y-1)-32)=0



Domain of the equation: 5(y+4)!=0

y∈R





Domain of the equation: 3(5y-1)-32)!=0

y∈R



We calculate fractions


(3y5/(5(y+4)*3(5y-1))+(-5yy/(5(y+4)*3(5y-1))+5=0

We can not solve this equation

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