1/5(y-3)=3/10(y+5)=-2/5y

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Solution for 1/5(y-3)=3/10(y+5)=-2/5y equation: 



1/5(y-3)=3/10(y+5)=-2/5y

We move all terms to the left:

1/5(y-3)-(3/10(y+5))=0



Domain of the equation: 5(y-3)!=0

y∈R





Domain of the equation: 10(y+5))!=0

y∈R



We calculate fractions


(10yy/(5(y-3)*10(y+5)))+(-15yy/(5(y-3)*10(y+5)))=0



We calculate terms in parentheses: +(10yy/(5(y-3)*10(y+5))), so:

10yy/(5(y-3)*10(y+5))

We multiply all the terms by the denominator


10yy

Back to the equation:

+(10yy)





We calculate terms in parentheses: +(-15yy/(5(y-3)*10(y+5))), so:

-15yy/(5(y-3)*10(y+5))

We multiply all the terms by the denominator


-15yy

Back to the equation:

+(-15yy)



We get rid of parentheses

10yy-15yy=0

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