1/5(z+2)=2/3(z-1)

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Solution for 1/5(z+2)=2/3(z-1) equation: 


z in (-oo:+oo)

(1/5)*(z+2) = (2/3)*(z-1) // - (2/3)*(z-1)

(1/5)*(z+2)-((2/3)*(z-1)) = 0

(1/5)*(z+2)+(-2/3)*(z-1) = 0

1/5*(z+2)-2/3*(z-1) = 0

1/5*(z+2)-2/3*(z-1) = 0

16/15-7/15*z = 0

16/15-7/15*z = 0

16/15-7/15*z = 0 // - 16/15

-7/15*z = -16/15 // : -7/15

z = -16/15/(-7/15)

z = 16/7

z = 16/7

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