1/5-2/5q=4/q

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Solution for 1/5-2/5q=4/q equation: 


D( q )

q = 0

q = 0

q = 0

q in (-oo:0) U (0:+oo)

1/5-((2/5)*q) = 4/q // - 4/q

1/5-((2/5)*q)-(4/q) = 0

(-2/5)*q-4*q^-1+1/5 = 0

1/5*q^0-2/5*q^1-4*q^-1 = 0

(1/5*q^1-2/5*q^2-4*q^0)/(q^1) = 0 // * q^2

q^1*(1/5*q^1-2/5*q^2-4*q^0) = 0

q^1

(-2/5)*q^2+(1/5)*q-4 = 0

(-2/5)*q^2+(1/5)*q-4 = 0

DELTA = (1/5)^2-(-4*4*(-2/5))

DELTA = -159/25

DELTA < 0

q in { } 

q belongs to the empty set

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