1/5-4/5a=4/a

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Solution for 1/5-4/5a=4/a equation: 


D( a )

a = 0

a = 0

a = 0

a in (-oo:0) U (0:+oo)

1/5-((4/5)*a) = 4/a // - 4/a

1/5-((4/5)*a)-(4/a) = 0

(-4/5)*a-4*a^-1+1/5 = 0

1/5*a^0-4/5*a^1-4*a^-1 = 0

(1/5*a^1-4/5*a^2-4*a^0)/(a^1) = 0 // * a^2

a^1*(1/5*a^1-4/5*a^2-4*a^0) = 0

a^1

(-4/5)*a^2+(1/5)*a-4 = 0

(-4/5)*a^2+(1/5)*a-4 = 0

DELTA = (1/5)^2-(-4*4*(-4/5))

DELTA = -319/25

DELTA < 0

a in { } 

a belongs to the empty set

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