1/5910x+20)+3/4x=25

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Solution for 1/5910x+20)+3/4x=25 equation: 



1/5910x+20)+3/4x=25

We move all terms to the left:

1/5910x+20)+3/4x-(25)=0



Domain of the equation: 5910x!=0

x!=0/5910

x!=0

x∈R





Domain of the equation: 4x-25!=0

We move all terms containing x to the left, all other terms to the right

4x!=25

x!=25/4

x!=6+1/4

x∈R



We calculate fractions


(4x-25)/(23640x^2-25)+3*5910x)/(23640x^2+20-25)=0

We add all the numbers together, and all the variables

(4x-25)/(23640x^2-25)+3*5910x)/(23640x^2=0

We calculate fractions


((4x-25)*23640x^2/((23640x^2-25)*23640x^2+17730x^2/((23640x^2-25)*23640x^2=0

We can not solve this equation

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