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1/5b+2/5b-5=-2
We move all terms to the left:
1/5b+2/5b-5-(-2)=0
Domain of the equation: 5b!=0We add all the numbers together, and all the variables
b!=0/5
b!=0
b∈R
1/5b+2/5b-3=0
We multiply all the terms by the denominator
-3*5b+1+2=0
We add all the numbers together, and all the variables
-3*5b+3=0
Wy multiply elements
-15b+3=0
We move all terms containing b to the left, all other terms to the right
-15b=-3
b=-3/-15
b=1/5
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