1/5b+33=35

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Solution for 1/5b+33=35 equation: 



1/5b+33=35

We move all terms to the left:

1/5b+33-(35)=0



Domain of the equation: 5b!=0

b!=0/5

b!=0

b∈R



We add all the numbers together, and all the variables

1/5b-2=0

We multiply all the terms by the denominator


-2*5b+1=0

Wy multiply elements

-10b+1=0

We move all terms containing b to the left, all other terms to the right

-10b=-1

b=-1/-10

b=1/10

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