1/5b=35

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Solution for 1/5b=35 equation: 



1/5b=35

We move all terms to the left:

1/5b-(35)=0



Domain of the equation: 5b!=0

b!=0/5

b!=0

b∈R



We multiply all the terms by the denominator


-35*5b+1=0

Wy multiply elements

-175b+1=0

We move all terms containing b to the left, all other terms to the right

-175b=-1

b=-1/-175

b=1/175

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