1/5f+24=4-1/5f

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Solution for 1/5f+24=4-1/5f equation: 



1/5f+24=4-1/5f

We move all terms to the left:

1/5f+24-(4-1/5f)=0



Domain of the equation: 5f!=0

f!=0/5

f!=0

f∈R





Domain of the equation: 5f)!=0

f!=0/1

f!=0

f∈R



We add all the numbers together, and all the variables

1/5f-(-1/5f+4)+24=0

We get rid of parentheses

1/5f+1/5f-4+24=0

We multiply all the terms by the denominator


-4*5f+24*5f+1+1=0

We add all the numbers together, and all the variables

-4*5f+24*5f+2=0

Wy multiply elements

-20f+120f+2=0

We add all the numbers together, and all the variables

100f+2=0

We move all terms containing f to the left, all other terms to the right

100f=-2

f=-2/100

f=-1/50

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