1/5f=2

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Solution for 1/5f=2 equation: 



1/5f=2

We move all terms to the left:

1/5f-(2)=0



Domain of the equation: 5f!=0

f!=0/5

f!=0

f∈R



We multiply all the terms by the denominator


-2*5f+1=0

Wy multiply elements

-10f+1=0

We move all terms containing f to the left, all other terms to the right

-10f=-1

f=-1/-10

f=1/10

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