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1/5g+2/5=-2(4+2/5)
We move all terms to the left:
1/5g+2/5-(-2(4+2/5))=0
Domain of the equation: 5g!=0We add all the numbers together, and all the variables
g!=0/5
g!=0
g∈R
1/5g+2/5-(-2(2/5+4))=0
We calculate fractions
()/625g+(-(-2(2*5g)/625g=0
We add all the numbers together, and all the variables
()/625g+(-(-2(+2*5g)/625g=0
We multiply all the terms by the denominator
(-(-2(+2*5g)+()=0
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