1/5g+2/5=-2(4+2/5)

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Solution for 1/5g+2/5=-2(4+2/5) equation: 



1/5g+2/5=-2(4+2/5)

We move all terms to the left:

1/5g+2/5-(-2(4+2/5))=0



Domain of the equation: 5g!=0

g!=0/5

g!=0

g∈R



We add all the numbers together, and all the variables

1/5g+2/5-(-2(2/5+4))=0

We calculate fractions


()/625g+(-(-2(2*5g)/625g=0

We add all the numbers together, and all the variables

()/625g+(-(-2(+2*5g)/625g=0

We multiply all the terms by the denominator


(-(-2(+2*5g)+()=0



We calculate terms in parentheses: +(-(-2(+2*5g)+(), so:

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